# A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

A. 9 sec
B. 10 sec
C. 7 sec
D. 6 sec

Solution:

$\left. \begin{array} { l } { \text { Speed of train relative to man : }}\\ { = ( 60 + 6 ) km / hr = 66 km / hr . } \\ { = ( 66 \times \frac { 5 } { 18 } ) m / sec } \\ { = ( \frac { 55 } { 3 } ) m / sec } \\ { \therefore \text { Time taken to pass the man :}}\\ { = ( 110 \times \frac { 3 } { 55 } ) sec = 6 sec } \end{array} \right.$