A. 100 m

**B. 150 m**

C. 200 m

D. 250 m

**Solution:**

\begin{array} { l } { \text { Speed } = ( 60 \times \frac { 5 } { 18 } ) m / sec = ( \frac { 50 } { 3 } ) m / sec } \\ { \text { Length of the train } = ( \text { Speed } x \text { Time) } } \\ { \therefore \text { Length of the train } = ( \frac { 50 } { 3 } \times 9 ) m}\\{ = 150 m } \end{array}