# qasd

asd

asd

Solution: Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 – x). $\left. \begin{array} { l } { \text { Then, } ( \frac { x \times 14 \times 2 } { 100 } ) + ( \frac { ( 13900 – x ) \times 11 \times 2 } { 100 } ) = 3508 } \\ { \Rightarrow 28 x – 22 x = 350800 – ( 13900 \times 22 ) } \\ { \Rightarrow 6 x = 45000 } \\ { \Rightarrow x = 7500 } \\ { \text { So, sum invested in Scheme } B:}\\ {= Rs . ( 13900 – 7500 ) = Rs .6400 } \end{array} \right.$