THis is the question for maths

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Solution: \[Then, \left(\frac{x\times14\times2}{100}\right)+\left( \frac{\left(13900-x\right)\times11\times2}{100}\right) = 3508 \\ \Rightarrow 28x-22x = 350800 - \left(13900 \times 22 \right)\\ \Rightarrow 6x = 45000 \\ \Rightarrow x = 7500\\ \text{So, sum invested in Scheme B:} \\ = Rs. \left(13900-7500\right) \\ =Rs. 6400\]

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